What is the output of the code snippet?
#include <stdio.h>
int main(void) {
char *s = "GATE2026";
printf("%s", s + 4);
return 0;
}s + 4 advances character pointer s by 4 bytes, pointing to the string starting at '2026'.
What happens when attempting to modify a character in a string literal via pointer: 'char *s = "hello"; s[0] = 'H';'?
String literals are stored in read-only memory text segment; modifying them causes undefined behavior or runtime crash.
What is the difference between pointer subtraction 'p2 - p1' where both point to elements of the same array?
Pointer subtraction evaluates to the number of array elements between the two pointers, automatically scaled by sizeof(T).
What will be printed by the program?
#include <stdio.h>
int main(void) {
int a[] = {1, 2, 3, 4, 5};
int *p = a;
printf("%d ", *p++);
printf("%d", *p);
return 0;
}*p++ yields the value *p (1) first, and then increments pointer p to point to the next element (2).
Consider 'int a[5] = {1, 2, 3, 4, 5};'. What is the value of '2[a]'?
Subscripting is commutative: 2[a] is equivalent to *(2 + a) = *(a + 2) = a[2] = 3.