What is the output of the following code?
#include <stdio.h>
int main(void) {
int a = 1, b = 2, c = 3;
int res = a < b < c;
printf("%d", res);
return 0;
}Relational operators associate left-to-right. (a < b) evaluates to 1 (true). Then (1 < c) evaluates to (1 < 3), which is 1.
What is printed by the following snippet?
#include <stdio.h>
int main(void) {
int x = 10, y = 20;
int max = (x > y) ? x : y;
printf("%d", max);
return 0;
}The ternary operator checks x > y (10 > 20, false), so it evaluates and returns y (20).
What is the evaluation result of the comma expression 'int x = (1, 2, 3);'?
The comma operator evaluates operands from left to right and returns the value of the last operand, which is 3.
What will be the output of this code?
#include <stdio.h>
int main(void) {
int a = 8;
printf("%d", a >> 2);
return 0;
}Right shift by 2 bits divides positive integer 8 by $2^2$ (4), giving 2.
What is the value of 'a' after 'a = ~0;' on a system where int is 32-bit two's complement?
Bitwise NOT of 0 (all 0 bits) produces all 1 bits, which in 32-bit signed two's complement representation equals -1.