Question 36
If L and $\bar{L}$ are recursively enumerable then L is
Step-by-Step Solution
Detailed Explanation:
By Post's Theorem, if both a language L and its complement $\bar{L}$ are recursively enumerable, then L is recursive (decidable).
If L and $\bar{L}$ are recursively enumerable then L is
Detailed Explanation:
By Post's Theorem, if both a language L and its complement $\bar{L}$ are recursively enumerable, then L is recursive (decidable).
S -> aSa | bSb | a | b. The language generated by the above grammar over the alphabet {a,b} is the set of:
Detailed Explanation:
Base productions S -> a | b generate single-character odd-length palindromes.
Recursive rules aSa and bSb add matching characters to both ends, maintaining odd length.
What is the highest type number that can be assigned to the following grammar?
S -> Aa, A -> Ba, B -> abc
• Type 3 (Regular Grammar) requires rules to be consistently left-linear (\(A \rightarrow Bw\)) or right-linear (\(A \rightarrow wB\)).
• Checking the given grammar rules:
\(S \rightarrow Aa\) is left-linear (Non-terminal + terminal)
\(A \rightarrow Ba\) is left-linear (Non-terminal + terminal)
\(B \rightarrow abc\) is pure terminals (Allowed in regular grammars)
Since all rules perfectly fit the criteria for a left-linear regular grammar, the highest type number it can be assigned is Type 3 .
Access time of the symbolic table will be logarithmic if it is implemented by
Detailed Explanation:
Balanced binary search trees (e.g., AVL trees, Red-Black trees) guarantee O(log n) access time for symbol table operations.
Recursive descent parsing is an example of
Detailed Explanation:
Recursive descent is a top-down parsing technique that builds the parse tree from the start symbol downward.