What will be printed by the following code snippet?
keys = ['a', 'b', 'c']
vals = [1, 2]
d = dict(zip(keys, vals))
print(d)
zip() stops as soon as the shortest input iterable is exhausted (vals length 2). Hence, d contains {'a': 1, 'b': 2}.
Find the output value of total:
d = {'p': 5, 'q': 10, 'r': 15}
total = sum(d.values()) - len(d)sum(d.values()) = 5 + 10 + 15 = 30. len(d) = 3. 30 - 3 = 27.
Which set operation corresponds to the operator - in Python (s1 - s2)?
The - operator computes set difference (elements present in s1 but absent in s2).
What will happen if we execute d = {}; d[[1, 2]] = 'val'?
Lists are mutable and unhashable, so they cannot serve as keys in a dictionary.
Evaluate len(s) after set comprehension:
s = {x % 4 for x in range(20)}
print(len(s))x % 4 for integer values produces remainder set {0, 1, 2, 3}. Length is 4.