Question 1
Find the minimum spanning distance and the corresponding number of edges for the following graph with vertices A, B, C, D, E and edge weights AB=1, AC=7, BC=5, BD=4, BE=3, CE=6, DE=2:
Step-by-Step Solution
Detailed Explanation:
$Vertices n = 5 (A, B, C, D, E). Minimum Spanning Tree must contain n - 1 = 4 edges.$
Select smallest edges avoiding cycles:
- AB = 1
- DE = 2
- BE = 3
- BC = 5
Total MST weight = 1 + 2 + 3 + 5 = 11.
Number of edges = 4.
Therefore, Option B (11, 4) is correct.