Question 1
Let A(1:8, -5:5, -10:5) be a three dimensional array. How many elements are there in the array A?
Step-by-Step Solution
Detailed Explanation:
Size of 1st dimension = (8 - 1 + 1) = 8
Size of 2nd dimension = (5 - (-5) + 1) = 11
Size of 3rd dimension = (5 - (-10) + 1) = 16
Total elements = 8 $\times 11 \times 16 = 1408$.